define resistance of a conductor class 10

[CBSE 2016], Two metallic wire A and B of the same material are connected in parallel. Answer: ∝ \(\frac{1}{A}\) Electric power determines the rate at which energy is delivered by a current. How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of (a) 4 Ω (b) 1 Ω? Direct current source of electromotive force. Compute the heat generated while transferring 96000 C of charge in one hour through a potential difference of 50 V. (d) 4 : 1 Materials having resistivity in the range of 10−8 Ω m to 10−6 Ω m are considered as very good conductors. Resistivity of mercury = 94.0 x 10-8 Ω m. Using Ohms law, V= I^1R^2 I^1 = V/(R^1) = 220/1200 = 0.18A And, I^2 = V/(R^2) = 220/100 = 2.2A, Resistance of each part = R/3 = 9/3 = 3Ω R^1 = R^2 = R^3 = 3Ω In parallel combination, 1/(R^p) = 1/(R^1) + 1/(R^2) + 1/(R^3) = 1/3 + 1/3 + 1/3 = 3/3 = 1 R^p = 1Ω, Given: P = 750 W, V = 220V (i) P = VI 750 = 220 × I I = 750/220 = 3.40A (ii) P = (V^2)/R R = (V^2)/R = (220^2)/R , R= 64.53Ω, Given: q= 1.6 × 10^-19 C, I= 1A, n=?, t=1s We know, q=It and q =ne ne = It n = (It )/(e ) = (1×1)/(1.6×10-19). While the rest of bulbs in parallel circuit will continue to glow without getting disturbed because in parallel combination, current gets additional paths to flow. 30 Days Study Plan for IBPS RRB Officer Scale 1 and Office Assistant Prelims, (i) directly proportional to square of current flowing through, (ii) directly proportional to resistance and. Find the number of electrons that will flow per second to constitute a current of 1 ampere. Answer: (i) We can get a total resistance of 4Ω by connecting the 2Ω resistance in series with the parallel combination of 3Ω and 6Ω. Whereas if we perform the same experiment with the help of a metallic wire such as copper, the bulb starts to glow. Advantages of connecting electrical devices in parallel: Question 4: Now inert the voltmeter across the ends of first resistor R^1. (fa) IR2, Question 3 (b) 330 mA Question 1: After stretching, if length increases by n times then resistance will increase by n2 times i.e., R2 = n2 R1. What is (a) the highest (b) the lowest total resistance that can be secured by combination of four coils of resistances 4 Ω, 8 Ω, 12 Ω, 24 Ω? [CBSE 2019], What is the name of physical quantity which is equal to V/I? Truly, this article is really one of the very best in the history of articles. Calculate (i) Its resistance while glowing (ii) energy consumed in kWh per day. Define its unit. Question 2 Question 4: Question 4 Solution: Resistance of a conductor (i) a directly proportional to its length, (ii) inversely proportional to its cross-section areas and depend on the material of the conductor.

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